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Mathematics 11 Online
OpenStudy (anonymous):

Evaluate integral of 2+x^2y ds where C is the upper half of x2 + y2 = 1 using the following naive parametrization for C: r(t)=, -1=

OpenStudy (anonymous):

this is a linear integral by the way

OpenStudy (anonymous):

x = cost, y = sint, 0 <= t <= pi ∫(2 + cos²t sint) √( (-sint)² + cos²t) dt ∫(2)dt + ∫cos²t sint dt = 2/3 + 2pi

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