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cos870° - sin780° = _____ -sq.root 3 sq. root 3 0
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cos (870) = cos (150) = - sqrt(3)/2 sin (780) = sin (60) = sqrt(3)/2 So, -sqrt(3)/2 - sqrt (3)/2 = -2sqrt(3)/2 = - sqrt(3) Note: an angle of 870 = an angle of 150, because every 360 it is periodic.
thank you so much! what about this one?? sin400° = _____ -sin40° sin40° <-- would it be this? sin(-40)°
@Easyaspi314
sin (400) = sin (40) Just subtract 360 from 400. Both angles are identical.
And you can easily verify this on your calculator: sin(400) = .6427876097 sin (40) = .6427876097
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so it would be the answer i chose right??
Yes the answer you have indicated is the correct one.
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