If a ball is thrown vertically upward from the roof of 32 foot building with a velocity of 64 ft/sec, its height after t seconds is s(t) = 32 + 64 t − 16 t2. What is the maximum height the ball reaches "in ft"? What is the velocity of the ball when it hits the ground (height 0) "in ft/sec"?
i got the first answer right with 96
but im not sure how to do number 2

Question

If a ball is thrown vertically upward from the roof of 32 foot building with a velocity of 64 ft/sec, its height after t seconds is s(t) = 32 + 64 t − 16 t2. What is the maximum height the ball reaches "in ft"? What is the velocity of the ball when it hits the ground (height 0) "in ft/sec"?
i got the first answer right with 96
but im not sure how to do number 2

ddcamp · Answer

We can find the time it takes to reach the ground by solving the position equation for s(t) = 0
Then, plug that time into the equation v = v₀ + at, with v₀=64 & a = -16

dan815 · Answer

have no fear ur best buddy is here

dan815 · Answer

|dw:1383196346961:dw|