Question

Find the first 4 terms of the taylor series for the function about the point a.

cos(theta) a=pi/4

Answer 1

i know cos(x)=1-x^2/2!+x^4/4!-x^6/6!+x^8/8!

Answer 2

can i just plug in a?

Answer 3

@dumbcow

Answer 4

not quite, that series assumes "a=0"

Answer 5

how do u know..then what do i do with a=pi/4

Answer 6

\[= \cos(a)-\sin(a)(x-a)-\frac{\cos(a)}{2}(x-a)^{2}+\frac{\sin(a)}{6}(x-a)^{3}\]
now just plug in "a = pi/4"

Answer 7

you are my savior tonight i hope you know!

Answer 8

well thank you :) ...but you can do it without me
just use the taylor series formula and do the derivatives

Answer 9

im starting to get the hang of it...kinda lol