Question

Finding solutions to a polynomial function?
Fan/medal for help?

Here is what I have so far:

5. First, we are going to find the possible rational zeros.

P= -240

Factors of P: ±1, ±2, ±3, ±4, ±5, ±6, ±8, ±10, ±12, ±15, ±16, ±20, ±24, ±30, ±48, ±60, ±80, ±120, ±240

Q= 1

Factors of Q: ±1
Simplified Factors of p/q: ±1, ±2, ±3, ±4, ±5, ±6, ±8, ±10, ±12, ±15, ±16, ±20, ±24, ±30, ±48, ±60, ±80, ±120, ±240
Next, we are going to find the possible number of real, negative real, and complex zeros.
How many times does the sign change in the original function?: 1
Positive zeros: 1

Answer 1

Next, we are going to find the possible number of real, negative real, and complex zeros.

How many times does the sign change in the original function?: 1
Positive zeros: 1

To find the negative zeros, we will substitute -x for each instance of x in the original function.

f(-x)=(-x)3=16(-x)2+48(-x)-240
f(-x)= -x3+16x2-48x-240

Answer 2

This is where I'm stuck, any and all help is most appreciated.