Given the function f(x) = 4(x+3) − 5, solve for the inverse function when x = 3. −21 −16 −10 −1
do you know how to find inverse function ?
hartnn that is y i asked the question cause i forgot how to find the inverse
ok, let y = 4(x+3) − 5 isolate 'x' from this equation. start by adding 5 on both sides.
ok so it would be 5+y=4(x+3)
yes, now divide by 4 on both sides...
ok so it would be \[\frac{ 5+y }{ 4 }=\frac{ x+3 }{ 4 }\]
on tight side, 4(x+3)/4 is just x+3 got this ? the 4 gets cancelled
oh ok
so, (5+y)/4 = x+3 just subtract 3 from both sides and you would have isolated 'x' ! :)
0k so when i subtract 3 do i subtract it from 5 or put it outside the perenthisis
outside paranthesis, as there is a fraction, keep the -3 alone on left side
ok so -3(5+y)/4=x
did you multiply ? its actually (5+y)/4 -3 = x ok ? so your inverse function is just (5+y)/4 -3
i mean (5+x)/4-3
now how do i get it to one of my answer options
we wanted inverse function when x=3 so just plug in x = 3 there!
ok so it would be 8/4=2-3=-1
correct! good work :)
another method to do the same thing is to put f(x) = 3 4(x+3) − 5 = 3 will also give you x = -1 :)
ok thanks man
welcome ^_^
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