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OpenStudy (luigi0210):
Can you determine the slope of each function?
OpenStudy (anonymous):
What do you think the answer is? How do you find the slope for each function?
OpenStudy (anonymous):
i think it is g(x)
OpenStudy (luigi0210):
You may be right, but find the slope just to be sure:
\[\LARGE \frac{15-14}{4-1}=?\]
OpenStudy (anonymous):
1/3
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OpenStudy (luigi0210):
Correct, so now we know the slope of h(x)
What is the slope of f(x)?
OpenStudy (anonymous):
what would i have to do? @Luigi0210
OpenStudy (luigi0210):
Well since f(x) is already in slope intercept form:
\[\LARGE y=mx+b\]
Just find what m is.
OpenStudy (anonymous):
4
OpenStudy (anonymous):
@Luigi0210
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OpenStudy (luigi0210):
4?
OpenStudy (luigi0210):
You sure about that?
OpenStudy (anonymous):
do i add 4+-2= im a bit confused @Luigi0210
OpenStudy (luigi0210):
No, you don't do anything special with this, just find what "m" is:
\[\LARGE y=5x+4\]
\[\LARGE y=mx+b\]
OpenStudy (anonymous):
so it equals 5 @Luigi0210
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OpenStudy (luigi0210):
Correct, so far we have:
\[h(x)=m=\frac{1}{3}\]
and \[f(x)=m=5\]
Now we need \[g(x)=m=?\]
OpenStudy (anonymous):
12-2? @Luigi0210 i dont know how many cubicles he passed
OpenStudy (luigi0210):
The points are: (0, 1) and (1, 3)
Do you see how I got these points?
OpenStudy (anonymous):
yes @Luigi0210
OpenStudy (anonymous):
do they all have the same y intercept? @Luigi0210
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OpenStudy (luigi0210):
Nope, so find the slope of this one:
\[\LARGE m=\frac{3-1}{1-0}=\]
OpenStudy (anonymous):
2/1
OpenStudy (luigi0210):
Correct, so now we have all 3 slopes, now you decide which one is the smallest c:
\[\LARGE f(x)=m=5\]
\[\LARGE g(x)=m=2\]
\[\LARGE h(x)=m=\frac{1}{3}\]
OpenStudy (anonymous):
h(x)
OpenStudy (luigi0210):
Yup :)
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