Question

1.Write the equation of a line parallel to the line 2x + 3y = 5 and passes through the point (9, -3)

A. y equals negative two-thirds x plus 3 B. y equals negative two-thirds x plus five-thirds
C. y = 2x – 21
D. y equals negative two-thirds x minus 9

2.Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).

A. y = -2x - 4
B. y = -2x - 8 C. y = -2x + 18
D. y = -2x – 12

Answer 1

3.Write an equation of a line in point-slope form that has a slope of -2 and passes through (5, -1).
A. y + 1 = -2(x – 5) B. y – 1 = -2(x – 5)
C. y – 5 = -2(x + 1)
D. y -5 = -2(x – 1)

Please help, i am pretty much failing everything. I have been very sick and just started this year and need to get caught up bad!

Answer 2

\[2x+3y=5\]
\[3y=5-2x\]
\[y=-\frac{ 2 }{ 3 }x-\frac{ 5 }{ 3 }\]
So the slope is going to be -3/5. Now plug in your point values for x and y into:
\[y=-\frac{ 2 }{ 3 }x+b\]
\[-3=-\frac{ 2 }{ 3 }*9+b\]
\[-3=-6+b\]
\[3=b\]

So the y intercept is 3 and the equation is \[y=-\frac{ 2 }{ 3 }x+3\]

Answer 3

Thank You