Question

help

Answer 1

All I know is 2. reflexive property. does anyone know 4

Answer 2

@Compassionate @jcari

Answer 3

Look at it. JK and KL are the same angle. Therefore, they're equal.

Answer 4

they arent equal. there is a property or theorem that proves that JK is larger than KL

Answer 5

Yes - both the sides are equal. Look at it closer. What theorum states that?

Answer 6

hinge theorem??

Answer 7

@hartnn

Answer 8

I think it's the retricepostulate.

Answer 9

Uhh. Angle-Angle-Side postulate.

Answer 10

But that would mean the triangles are congruent and they arent congruent

Answer 11

Two sides of the two triangles are the same. But the included angle of one is greater than the included angle of the other. So the side opposite to the greater angle will be greater than the side opposite to the smaller angle. The law of cosines can prove that.

Answer 12

JK^2 = JM^2 + MK^2 - 2(JM)(MK)cos(JMK) ---- (1)
KL^2 = ML^2 + MK^2 - 2(ML)(MK)cos(KML) ----- (2)
ML = JM in (2)
KL^2 = JM^2 + MK^2 - 2(JM)(MK)cos(KML) ----- (3)
Subtract (3) from (1)
JK^2 - KL^2 = 2(JM)(MK)[ cos(KML) - cos(JMK) ]
angle JMK > angle KML. So cos(KML) > cos(JMK) (because cosine decreases when the angle goes from 0 to 180 degrees).
Therefore, JK^2 - KL^2 is positive. So JK > KL

Answer 13

Thanks @ranga

Answer 14

Glad to be able to help.