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Mathematics 42 Online
OpenStudy (anonymous):

Write a two column proof.

OpenStudy (anonymous):

Directrix (directrix):

@imnoone Please post a larger diagram. Or, post what is given about the two triangles and what it is you want to prove. Thanks.

OpenStudy (anonymous):

@Directrix

Directrix (directrix):

Are you supposed to write this proof from scratch or do you have some of the statements and reasons already given to you as part of the problem?

OpenStudy (anonymous):

@Directrix I'm supposed to write it from scratch :/

OpenStudy (anonymous):

So far I have MN is congruent to PN - Given LM is congruent to LP - Given and thats it haha

Directrix (directrix):

I am going to try to get the statements together and then you can do the reasons. I'll have to think a few minutes.

OpenStudy (anonymous):

@Directrix thanks, sounds good!

Directrix (directrix):

The first step in a proof is to take the diagram and mark on the diagram what is given. That helps a person figure out what to do to get to the "to prove." Here is our diagram.

Directrix (directrix):

Then, think back on ways to prove triangles congruent and see if any of them might apply here, and, if so, how. So, attached is a visual of ways to prove triangles congruent.

Directrix (directrix):

A is for angle (we have none); S is for side (we have two pairs); H is for hypotenuse (we do not know we have right triangles so that is out); and L is for leg of a right triangle so that is out.

Directrix (directrix):

@imnoone Look at the marked up diagram. Do you see any way to get segment LN congruent to itself. That is, segment LN ≅ segment LN ? Because if you could, we would have 3 sides of one triangle congruent to three sides of another triangle. Then, the SSS postulate would make the two triangles congruent. Don't worry - we will write the proof but we have to do some thinking first. I am asking you about this: segment LN ≅ segment LN Do you know of any reason ^^^ might be true?

OpenStudy (anonymous):

@Directrix I've been reading this over and over and I'm still not getting it ugh

Directrix (directrix):

Do you remember the property that states that a segment is congruent to itself? That is what I am asking. segment LN ≅ segment LN Or, maybe 5 =5 --> that property?

OpenStudy (anonymous):

@Directrix the reflexive property?

Directrix (directrix):

Correct. We're ready now. I marked that on the diagram. Here it is:

OpenStudy (anonymous):

@Directrix okay so so far I have MN is congruent to PN - Given LM is congruent to LP - Given LN is congruent to LN - Definition of the Reflexive Property

Directrix (directrix):

Given: Seg MN ≅ Seg PN; Seg LM ≅ Seg LP Prove: Tri MLN ≅ Tri PLN -------------- Statements Reasons --------------- 1. Seg MN ≅ Seg PN 1. Given 2. Seg LM ≅ Seg LP 2. Given 3. Seg LN ≅ Seg LN 3. Reflexive Property of Congruency 4. Triangle MLN ≅ Triangle PLN 4. @imnoone I typed in your statements and reasons from above. So, we have one reason left to do, and we are finished. Once you got started, you did well.

Directrix (directrix):

@imnoone How do we know that these triangles are congruent? Look at that chart of ways to prove triangles congruent, okay?

OpenStudy (anonymous):

@Directrix so I do put what kind of triangle it is for number 4?

Directrix (directrix):

No. We don't know what kind of triangles they are.

OpenStudy (anonymous):

ugh

Directrix (directrix):

We are looking at ways to prove triangles congruent. ASA Postulate, SSS Postulate, SAS Postulate --> It is one of those.

Directrix (directrix):

Here's a BIG hinit from earlier in this thread: Look at the marked up diagram. Do you see any way to get segment LN congruent to itself. That is, segment LN ≅ segment LN ? Because if you could, we would have 3 sides of one triangle congruent to three sides of another triangle. **Then, the SSS postulate would make the two triangles congruent.** @imnoone

OpenStudy (anonymous):

@Directrix I'm guessing its the SSS postulate?

Directrix (directrix):

That is correct.

Directrix (directrix):

In the proof above, you can write "SSS Postulate." And, it is done!

OpenStudy (anonymous):

@Directrix thank you so much! I'm sorry it takes me awhile to understand

Directrix (directrix):

That is the way it goes with these proofs. But, you will get better with practice. Everybody gets confused when first learning this.

OpenStudy (anonymous):

@Directrix hopefully! thanks again :)

Directrix (directrix):

You are welcome.

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