Mathematics
10 Online
OpenStudy (anonymous):
Find the value of x.
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OpenStudy (anonymous):
OpenStudy (anonymous):
imnoon ever heard of patagerom therom?
OpenStudy (anonymous):
pythagorean theorem my bad
OpenStudy (anonymous):
@Reaper534 yup
OpenStudy (anonymous):
|dw:1383261000844:dw|
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OpenStudy (anonymous):
|dw:1383261064911:dw|
OpenStudy (anonymous):
\[a ^{2}+b ^{2}=c ^{2}\]
OpenStudy (anonymous):
plug in a b and c
x^2+1^2=8^2 right ranga?
OpenStudy (ranga):
Side A and B are equal as indicated by the mark on those two sides.
OpenStudy (anonymous):
@Reaper534 so x^2 + 1 =16?
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OpenStudy (ranga):
Two sides of the right triangle are x each. The hypotenuse is 8. Solve for x.
OpenStudy (ranga):
\[\Large x^{2} + x^{2} = 8^{2}\]
OpenStudy (anonymous):
I dont understand how to get x?
OpenStudy (anonymous):
mmm 2x^2=8^2 next right?
OpenStudy (anonymous):
ive done these kind or problems but not like this one yet
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OpenStudy (anonymous):
its confusing
OpenStudy (anonymous):
it is
OpenStudy (anonymous):
@ranga do you know how to solve for x?
OpenStudy (ranga):
2x^2 = 8^2 = 8 x 8 = 64
divide both sides by 2
x^2 = 32
take square root on both sides
x = sqrt(32) = sqrt(16 * 2) = 4sqrt(2)
\[x = 4\sqrt{2}\]
OpenStudy (anonymous):
I hope someday ill be as smart as you ranga
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OpenStudy (anonymous):
@ranga thank you so much!! xx
OpenStudy (ranga):
Glad to be able to help.