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Mathematics 10 Online
OpenStudy (anonymous):

Find the value of x.

OpenStudy (anonymous):

OpenStudy (anonymous):

imnoon ever heard of patagerom therom?

OpenStudy (anonymous):

pythagorean theorem my bad

OpenStudy (anonymous):

@Reaper534 yup

OpenStudy (anonymous):

|dw:1383261000844:dw|

OpenStudy (anonymous):

|dw:1383261064911:dw|

OpenStudy (anonymous):

\[a ^{2}+b ^{2}=c ^{2}\]

OpenStudy (anonymous):

plug in a b and c x^2+1^2=8^2 right ranga?

OpenStudy (ranga):

Side A and B are equal as indicated by the mark on those two sides.

OpenStudy (anonymous):

@Reaper534 so x^2 + 1 =16?

OpenStudy (ranga):

Two sides of the right triangle are x each. The hypotenuse is 8. Solve for x.

OpenStudy (ranga):

\[\Large x^{2} + x^{2} = 8^{2}\]

OpenStudy (anonymous):

I dont understand how to get x?

OpenStudy (anonymous):

mmm 2x^2=8^2 next right?

OpenStudy (anonymous):

ive done these kind or problems but not like this one yet

OpenStudy (anonymous):

its confusing

OpenStudy (anonymous):

it is

OpenStudy (anonymous):

@ranga do you know how to solve for x?

OpenStudy (ranga):

2x^2 = 8^2 = 8 x 8 = 64 divide both sides by 2 x^2 = 32 take square root on both sides x = sqrt(32) = sqrt(16 * 2) = 4sqrt(2) \[x = 4\sqrt{2}\]

OpenStudy (anonymous):

I hope someday ill be as smart as you ranga

OpenStudy (anonymous):

@ranga thank you so much!! xx

OpenStudy (ranga):

Glad to be able to help.

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