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The redox reaction of peroxydisulfate with iodide has been used for many years as part of the iodide clock reaction which introduces students to kinetics. If E not cell equals 1.587V and E not redox of the anode half cell is 0.536V, what is E not redox of the cathode half cell? S2O82-(aq) + 2H+ +2I-(aq) yields 2HSO4-(aq) + I2 (aq) A. -1.051V B. 1.051V C. -2.123V D. 2.123V E. None of these choices is correct
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\(E_{cell}=E_{cathode}-E_{anode}\)
So 1.587V-0.536V=1.051V
yep
Thanks
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