Question

integration (polar coordinates) HELP!

Answer 1

\[\int\limits_{0}^{2}\int\limits_{0}^{\sqrt{2x-x^2}} \sqrt{x^2 +y^2} dydx\]

Answer 2

converting to polar coordinates.

Answer 3

i know i got to get R through make y=sqrt(2x-x^2) and i got x^2+y^2=2x therefore R=sqrt(2x) right?

Answer 4

NOW i need to draw a graph to get limits of theta

Answer 5

do you see what i wrote so far?

Answer 6

we need to get the radius first

Answer 7

i got sqrt(2x) for radius

Answer 8

so limit for R is 0 to sqrt(2x)