Factor completley. 6x^2+20x+16.
you can divide all terms by 2
not GCF, factor the trinomial.
simplify it... you get 3x^2+10x+8
A(2x+1)(3x-5) B.(3x+1)(3x-6) C.(6x+1)(4x-1) D.(x-3)(6x-4)
then factor ok just multiply what you have then using foil method
3x^2+6x+4x+8 3x(x+2)+4(x+2)
....nevermind, that doesnt really help, to factor trinomials is different from factoring a regular algebraic equation you have to take the middle term, and find two number that are equal substitute them......but that all i know how to do. Thank you for your help though.
weird none of your las terms multiplied = 16 or 8 anyway 2(3x +4)(x + 2)
none of the 'answers' you listed are the correct answer
yup ......@Zarkon
(3x+4)(x+2) the correct ans is this
weird none of your las terms multiplied = 16 or 8 anyway 2(3x +4)(x + 2) no --this is the correct answer
zpupster has the correct answer
but both the ans are correct
the correct answer according the the answer key is (3x+4)(2x+4)
and sorry i posted the wrong choices.
that is equivalent to zpupster's answer
yup..
\[2(3x +4)(x + 2)=(3x +4)2(x + 2)=(3x +4)(2\cdot x + 2\cdot2)\] \[(3x +4)(2x + 4)\]
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