what is the equationof the line that passes though (4,-1) and (-2,3)

Question

cwrw238 · Answer

first find the slope of the line using the formula   y2 - y1
                                                                            ------
                                                                            x2 - x1

where the 2 points are (x1,y1) and (x2, y2)

cwrw238 · Answer

in you case (x2,y2)  can be  (-2,3)
in other words x2 = -2 and y2 = 3

anonymous · Answer

you can assign point P1 (4, -1) and point P2 (-2, 3)...
as @cwrw238 said, find the slope first...
then you can complete the line equation using the Point-Slope form...
$$(y - y1) = m (x - x1) $$

cwrw238 · Answer

m is the slope  and you are given  x1 and y1

anonymous · Answer

x+2=-2/3(y-4)