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Linear Algebra
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OpenStudy (anonymous):
What are the x– and y–intercepts of the quadratic equation y = (x – 3)2 – 25? Identify the x–intercepts by graphing the quadratic equation.
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OpenStudy (anonymous):
\[ y = (x – 3)2 – 25\]\[ y = 2x – 6 – 25\]\[y=2x-31\]
can you do it now?
OpenStudy (anonymous):
no im still confused on what that is ... it doesnt give me a graph to grap it on
OpenStudy (anonymous):
You dan't need to, plug in 0 for x to find y intercept and plug 0 for y to find the x intercept.
OpenStudy (cwrw238):
don't you mean (x - 3)^2 - 25?
OpenStudy (anonymous):
maybe, i readf it as w/o a cerokee.
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OpenStudy (cwrw238):
the y intercept occurs when x = 0
OpenStudy (cwrw238):
so when x = 0
y = (0-3)^2 - 25
can you work that out?
OpenStudy (anonymous):
i got that one but i havent gotten an of the others yet what is the next step? can you help me
OpenStudy (cwrw238):
do you mean how to get the x-intercepts?
OpenStudy (anonymous):
yes that is what i am talking about
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OpenStudy (cwrw238):
ok at the x intercepts y = 0
so you need to solve
(x-3)^2 - 25 = 0
adding 25 to both sides
(x-3)^2 = 25
can you continue form here?
OpenStudy (anonymous):
thank you
OpenStudy (cwrw238):
yw
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