Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
(– 2, – 16), and x intercepts at x = -6 and x = 2. (Do not include the negative sign in your answer.)
y = x2 + 4x − ___
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OpenStudy (anonymous):
@ranga
OpenStudy (ranga):
If p and q are the roots, then the quadratic equation will be: y = a(x - p)(x - q)
Here p = -6 and q = 2. Substitute in the above equation.
You can find a knowing that the vertex lies on the curve. So put x = -2, y = -16 and solve for a.
OpenStudy (anonymous):
what about q
OpenStudy (anonymous):
Oops i see
OpenStudy (anonymous):
@ranga a equals 1
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OpenStudy (ranga):
yes.
OpenStudy (anonymous):
Thats right!?
OpenStudy (anonymous):
y = x2 + 4x −1
OpenStudy (ranga):
yes a = 1. The equations is: y = x^2 + 4x - 12
OpenStudy (anonymous):
the one goes there like that
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OpenStudy (anonymous):
The equations is: y = x^2 + 4x - 12 so the answer is 12?
OpenStudy (ranga):
yes.
OpenStudy (anonymous):
I thought u said the answer was 1
OpenStudy (ranga):
No, the value of "a" = 1. With a = 1, y = a(x - p)(x - q) becomes
y = (x + 6)(x - 2) = x^2 + 4x - 12
And the blank in the answer is 12.
OpenStudy (anonymous):
OHHH Thanks so much btw is that you in the picture
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OpenStudy (ranga):
yes and two dogs.
OpenStudy (anonymous):
I love the picture I didn't even notice the dogs the lol