Question

what is an equation for the line that passes through points (-1,-4) and (1,4). Write the equation in slope-intercept form.

Answer 1

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&(-1\quad ,&-4)\quad &(1\quad ,&4)
\end{array}
\\\quad \\

slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}
\\ \quad \\\\ \quad \\ \quad \\

y-y_1=m(x-x_1)\qquad \textit{plug in your values and solve for "y"}\)

Answer 2

I got 8=m(2)

Answer 3

\(\bf slope = m= \cfrac{rise}{run} \implies \cfrac{4-(-4)}{1-(-1)}
\implies \cfrac{8}{2}\implies 4\)

Answer 4

\(\bf \begin{array}{lllll}
&x_1&y_1\\
&(-1\quad ,&-4)
\end{array}
\\\quad \\
y-y_1=4(x-x_1)\) you could use either point really, I just happen to use the 1st one, the 2nd one will work just fine as well