Question

If the length of a large banner is 4x + 5 and the width is half as long, what is the area?



A. 6x² + 20x + 12.5
B. 8x² + 17x + 12.5
C. 8x² + 20x + 12.5
D. 8x² + 22x + 12.5

Answer 1

2x+2.5 multiplied by 4x+5

Answer 2

area = l x w
length = 4x +5
width = (4x+5)/2

(4x + 5 )(2x + 2.5)

Answer 3

The area of a rectangle is it's length time its width.
\[A = ( length)(width)\]
The width is the same as half the length.
\[A = (length) \left( \frac{ length }{ 2 } \right)\]
The length is equal to 4x+5.
\[A = (4x+5)\left( \frac{ 4x+5 }{ 2 } \right)\]
You can put the half out of the operation.
\[A=\frac{ (4x+5)(4x+5) }{ 2 }=\frac{ (4x+5)^2 }{ 2 }\]

Answer 4

\[\frac{ (4x+5)^{2} }{ 2 }= \frac{ 16x^{2} + 40x + 25 }{ 2 }=8x^{2} + 20 x + 12.5\]

Answer 5

And. That's the area.

Answer 6

thanks for your great explanation everyone @Lessis