Question

Inbox Me If You're Willing To Help Me Out With Few Problems Thank You

Answer 1

it is better to just post your problems. one by one .

Answer 2

I know but it takes kind of long

Answer 3

Hello Good morning

Answer 4

Loll Hi

Answer 5

@wolf1728

Answer 6

Any problems to post?

Answer 7

yes but i'm being timed so i dont have much time

Answer 8

What is the value of the coefficient "b" when the quadratic equation y = (3x − 5)(2x + 3) is written in standard form?

19

6

−15

−1

Answer 9

(3x − 5)(2x + 3)
6x² -10x +9x-15
So b = -1

Answer 10

ok ty

Answer 11

Solve 3x2 + x + 10 = 0. Round solutions to the nearest hundredth.

x ≈ −2.83 and x ≈ 0.83

No real solutions

x ≈ −2.01 and x ≈ 1.67

x ≈ −1.67 and x ≈ 2.01

Answer 12

No real solutions

Answer 13

ty

Answer 14

What are the exact solutions of x2 + 5x + 2 = 0?

x = the quantity of negative 5 plus or minus the square root of 33 all over 2

x = the quantity of 5 plus or minus the square root of 33 all over 2

x = the quantity of negative 5 plus or minus the square root of 17 all over 2

x = the quantity of 5 plus or minus the square root of 17 all over 2

Answer 15

{ -5 ± Sq Root ( 25 - 8 ) } / 2
x = the quantity of negative 5 plus or minus the square root of 17 all over 2
(THIRD ANSWER down

Answer 16

Ty

Answer 17

Identify the solutions of 3x2 − x − 4 = 0.

x = −1 over 3, x = 4

x = 1 over 3, x = −4

x = 4 over 3, x = −1

x = −4 over 3, x = 1

Answer 18

x = 4 over 3, x = −1
THIRD ANSWER down

Answer 19

ty

Answer 20

Identify the vertex for the graph of y = −2x2 + 8x − 1.

(−2, 7)

(2, 7)

(2, −9)

(−2, −9)

Answer 21

2, 7
SECOND ANSWER

Answer 22

ty

Answer 23

Determine whether the graph of y = x2 − 4x + 1 has a maximum or minimum point, then find the maximum or minimum value.

Minimum; (2, -3)

Maximum; (2, -3)

Minimum; (-3, 2)

Maximum; (-3, 2)

Answer 24

Minimum; (2, -3)
FIRST ANSWER

Answer 25

alright

Answer 26

Where does the graph of y = 2x2 − 5x + 3 cross the x-axis?

(−1 over 2, 0) and (−3, 0)

(1 over 2, 0) and (3, 0)

(3 over 2, 0) and (1, 0)

(−3 over 2, 0) and (−1, 0)

Answer 27

(3 over 2, 0) and (1, 0)
THIRD ANSWER

Answer 28

alright

Answer 29

Determine whether the graph of y = 2x2 − 3x − 17 opens up or down and whether it has a maximum or minimum point.

Up; Maximum

Up; Minimum

Down; Minimum

Down; Maximum

Answer 30

a is positive so it opens upward - concavwe up

Up; Minimum
SECOND ANSWER

Answer 31

Ok

Answer 32

Katie wants to hang a painting in a gallery but the painting and frame must have an area of 45 square feet. The painting is 6 feet wide by 7 feet long. The frame must have an equal width of x on each side. Which quadratic equation represents the area of the painting and frame combined?

Answer 33

4x2 + 26x + 45 = 0

4x2 + 26x − 3 = 0

x2 + 13x − 3 = 0

x2 + 13x + 45 = 0

Answer 34

Not too sure - probably
x2 + 13x − 3 = 0

Answer 35

Ok :)

Answer 36

For y = x2 + 6x − 16,

Determine if the parabola opens up or down.
State if the vertex will be a maximum or minimum.
Find the vertex.
Find the x-intercepts.
Describe the graph of the equation.

Answer 37

How much longer?

Answer 38

Last two

Answer 39

Opens up
Minimum
(-3. -25)
(2, -8)
Concave Up

Answer 40

Could you describe it more like in two sentences

Answer 41

It looks like a 'U'

Answer 42

No I'm saying you mind explaining how you got your answers please

Answer 43

Geez - explain what I just typed?

Opens up because 'a' is positive
Minimum - because 'a' is positive
(-3. -25) vertex -found by taking derivative of x² + 6x -16 = 2x + 6
x=2 x= -8 x intercepts are where graph crosses x axis
Concave Up

Answer 44

Hey now please be cooperative I really appreciate your help I just need one more

Answer 45

Create your own quadratic equation that cannot be solved by factoring, but can be solved using the quadratic formula. Identify the values of a, b, and c, and find the solutions using the quadratic formula. Show all work to receive credit.

Part 2: Using complete sentences, explain how you know that the equation from Part 1 cannot be solved by factoring, but can be solved by using the quadratic formula.

Answer 46

x ² + 2 x + 6 = 0
a=1 b=2 c=6

x = -2 +- (sqrt(4 - 4 * 1 * 6) / 2*1
x = -2 +- (sqrt 4 -24) / 2
x = -2 +- sqrt (-20) / 2
x1 = (-2 +4.472135955 i) / 2
x2 = (-2 -4.472135955 i) / 2

I knew this equation could not be solved by factoring because b² - 4 a c is negative causing imaginary roots.

Answer 47

You're amazing dude thankß I am going to do a testimonial are you a male or a female

Answer 48

Male and thanks !!

Answer 49

Yw and thanks again !!