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Mathematics 14 Online
OpenStudy (anonymous):

2*2^2x=4^x+64

hartnn (hartnn):

is it \(\large 2\times 2^{2x}=4^x+64\) if yes, then note that 2^2 =4 so, 2^2x =4^x so, can you isolate 4^x from that equation?

OpenStudy (anonymous):

Yes that's the correct equation. I am trying to solve using like bases. I know the answer is 3. I just can't get past 2*2^2x=2^2x+2^6

hartnn (hartnn):

ok, so to simplify things lets take 4^x = a you got how 2^2x = 4^x ?? so, we have 2a =a+64 can you find 'a' from here ? or 4^x

OpenStudy (anonymous):

But doesn't that make the answer 64?

hartnn (hartnn):

a= 64 so, 4^x = 64 can you now express 64 as a power of 4 ?

hartnn (hartnn):

\(\large 64=4^{??} \\ \large 4^x = 4^{??} \\ x= ??\)

OpenStudy (anonymous):

Okay I got it now thank you so much

hartnn (hartnn):

welcome ^_^ \(\Huge \mathcal{\text{Welcome To OpenStudy}\ddot\smile} \)

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