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2*2^2x=4^x+64
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is it \(\large 2\times 2^{2x}=4^x+64\) if yes, then note that 2^2 =4 so, 2^2x =4^x so, can you isolate 4^x from that equation?
Yes that's the correct equation. I am trying to solve using like bases. I know the answer is 3. I just can't get past 2*2^2x=2^2x+2^6
ok, so to simplify things lets take 4^x = a you got how 2^2x = 4^x ?? so, we have 2a =a+64 can you find 'a' from here ? or 4^x
But doesn't that make the answer 64?
a= 64 so, 4^x = 64 can you now express 64 as a power of 4 ?
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\(\large 64=4^{??} \\ \large 4^x = 4^{??} \\ x= ??\)
Okay I got it now thank you so much
welcome ^_^ \(\Huge \mathcal{\text{Welcome To OpenStudy}\ddot\smile} \)
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