solve for x: sin3x=-cosx
it is sin^3 or just sin3x???
sin3x..... Its not raised to the power of 3
sin(3x) = sin(x+2x) this help?
you have 2 identities to deal with
@gopZ
Cos(90-3x)= -cosx , because cos90-x=sinx ryt?
yes and -cos(x) = cos(180-x) so 90-3x = 180 - x solve for x
but that only captures 1 of 3 solutions
Then lets find the general solution
sorry for delay...here use sum to product identity http://en.wikipedia.org/wiki/Trig_Identity#Product-to-sum_and_sum-to-product_identities \[\cos(90-3x) + \cos x = 0\] \[2\cos(\frac{90-2x}{2}) \cos(\frac{90-4x}{2}) = 0\] \[\cos(45-x) \cos(45-2x) = 0\] ...
@dumbcow, ive been trying to award you with a medal but dis freakin' phone im using does not work properly with dis site! Anyway thanx for ur help
haha no worries :)
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