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Solve -3x^2+3-x=90=0 using quadratic formula
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@Kainui
here are the choices:
Since 30 is not an odd number, its fine to use the completing the square method, but i dont really like it
\[x1,2 = \frac{ -30\pm \sqrt{30^2-4\times(-3)\times(-90)} }{ 2\times(-3) }\]
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i got it, but im stuck on the last step
\[x1,2 = 5 \pm \frac{ \sqrt{-180} }{ -6 } \]
wait why the 5?
its supposed to be a 30
oh i get it
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now we can insert the -6 into the square root - it becomes 36: \[x1,2 = 5 \pm \sqrt{\frac{ -180}{ 36 }}\]
now -180/36 = -5 so square root of -5 is i times square root of 5
ok?
ok its B thanks
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