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Algebra
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Solve by completing the square: x^2-12x-5=0
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I know that you add 5 so it would be: x^2-12x+_c_=5 Then I dont know how to find C?
x^2-12x-5=0 x^2-12x=5 Move the number(without the variable) over to the other side.
take half of 12x, and square it
Then to find C I half 12 then square it and that would be 36 right?
x^2-12x+36=41
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SO: (x-6)^2=square root of + or-41
hmmm usually you'd want to group the "x" terms or like-terms
36 + -12x + x^2 = 41 Factor a perfect square on the left side (x + -6)(x + -6) = 41
i think you're on the hang of it
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