The function f(x) = 16(5)x represents the growth of a bee population every year in a remote swamp. Jennifer wants to manipulate the formula to an equivalent form that calculates two times a year, not just once a year. Which function is correct for Jennifer's purpose, and what is the new growth rate?
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OpenStudy (anonymous):
dividde by 2? maybe?
OpenStudy (anonymous):
8(5)x
OpenStudy (anonymous):
8(5)^2x?
OpenStudy (anonymous):
whateve it is divide the whole thing by 2 i suppose :)
OpenStudy (anonymous):
or i could be wrong
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OpenStudy (anonymous):
I think you leave it the same lol :P
OpenStudy (anonymous):
ooo okay :3 thank you
OpenStudy (anonymous):
wait for second opinion tho
OpenStudy (anonymous):
I feel it is a trick question
OpenStudy (anonymous):
haha i feel like all math is a trick
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OpenStudy (anonymous):
well lets play around with it
16(5)^2(1)=400 for 1 year in original eq 16(5)^2(x)
16(5)^2(2*1/2)=400 for 1 year in modified equation 16(5)^2(x*1/2)
i think your new function should be this but now your have units of half years instead of years.
16(5)^2(x*1/2)