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Mathematics 8 Online
OpenStudy (anonymous):

the perimeter of a rectangle is 120 meters. if the length of the rectangle is 20 meters more than the width, what are the dimensions of the rectangle? is there an easier way than trial and error?

OpenStudy (anonymous):

@ludwig457

OpenStudy (anonymous):

yes LETS DRAW

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

i'll draw a picture if you want to see what i mean

OpenStudy (anonymous):

you know perimeter formula?

OpenStudy (anonymous):

2w+2l=perimeter

OpenStudy (anonymous):

|dw:1383529103809:dw|

OpenStudy (anonymous):

|dw:1383529127473:dw|

OpenStudy (anonymous):

|dw:1383529234260:dw| think of it like that

OpenStudy (anonymous):

its longer than it is wide

OpenStudy (anonymous):

yes, by 20 meters

OpenStudy (anonymous):

substitute those values into your perimeter formula

OpenStudy (anonymous):

2(20+2)+2(w)=120

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

2(20+w)**

OpenStudy (anonymous):

it should've been a 2

OpenStudy (anonymous):

i mean a w sorry

OpenStudy (anonymous):

lol k

OpenStudy (anonymous):

what do you get to =120

OpenStudy (anonymous):

2(20+w)+2(w)

OpenStudy (anonymous):

distribute the 2 so it becomes (40+w) +2w =120 after that, no clue

OpenStudy (anonymous):

(40+w) +2w =120 --> 40+3w=120 ?|dw:1383529953620:dw|

OpenStudy (anonymous):

|dw:1383530796405:dw|

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