Question

Will my graph look like mine attached? Fro:
V (x) = −(x + 2)^3(x −1)^3(x − 4)^2

Answer 1

http://www.wolframalpha.com/input/?i=+%E2%88%92%28x+%2B+2%29^3%28x+%E2%88%921%29^3%28x+%E2%88%92+4%29^2

Answer 2

i tried

Answer 3

the minus sign makes it open down
look at the link i attached

Answer 4

that's right i forgot that thanx

Answer 5

yw

Answer 6

V (x) = −(x + 2)^3(x −1)^3(x − 4)^2
The leading term is: (-1)(x^3)(x^3)(x^2) = -(x^8)
The degree of the leading term is even and the coefficient is negative.
Therefore, the end points are gonna be like -x^2 or an inverted U (only the end points).
Left end down and right end down.

The function obviously has the roots: -2, 1, 4.
Those are the points where the curve cuts or touches the x axis.
The root x =-2 has multiplicity of 3. Odd multiplicity so the curve will cut the x axis at x = -2. Same conclusion for the root x = 1.
The root x = 4 has even multiplicity and so the curve will touch the x axis at x = 4.

You can put x = 0 and find the y intercept: -(2^3)(-1)^3(-4)^2 = 128.

Enough info to plot the graph.

Answer 7

ohhh okay thank you im going to try some more brb

Answer 8

alright.