Question

Calculate the derivative of the function
g(x) = (x^2 − 3x − 1)^−6

Answer 1

i got -6(x^2-3x-1)(-3) but its incorrect

Answer 2

there should be a -6(x^2-3x-1)^-7, I believe

Answer 3

@kbchick1 what do you mean? that should be the answer?

Answer 4

nX^n-1 when n is any real number so It should be -6(x^2-3x-1)^-6-1

Answer 5

no that's not the final answer

Answer 6

The next part should be like (2x-3) I think lol

Answer 7

Pretty sure, yeah. derivative of x^2 is 2x and derivative of 3x is 3(1) and deri of any number is 0

Answer 8

@kbchick1 thats not how you do it lol

Answer 9

Too much confusion. I'll just settle it.

\(g(x) = (x^{2} − 3x − 1)^{−6}\)

\(g'(x) = (-6)(x^{2} − 3x − 1)^{−7}\cdot(2x-3)\)

Answer 10

that's what I said lol