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tan(arcsin(x/5))=
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|dw:1383540754562:dw|
theta is the angle where the sin is x/5. So what would be the tan of theta? It will be x/? You find ? using Pythagorean Theorem.
tan=sin/sqrt(1-sin^2). sin(arcsin(x))=x. tan(arcsin(x))=x/sqrt(1-x^2). Thus tan(arcsin(x/5))=(x/5)*1/sqrt(1-(x/5)^2))
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