Question

Write the equation of the line that is parallel to the line 3x - y = -3 and passes through the point (4, -2).

y = -one thirdx - 6

y = -one thirdx - 14

y = 3x - 6

y = 3x - 14

Answer 1

You can rearrange the given equation into point-slope form and then find the slope ... once you find the slope the parallel line should have the same number for slope and you can construct the equation using a new point-slope equation

Answer 2

where point slope form is
\[y - y_1 = m(x - x_1)\]
which is a line of slope m that passes through point (x1, y1)

Answer 3

y--2=m(x-4)
y+2=m(x-4)

Answer 4

rearranging the given equation you should find
y = 3(x + 1)

Answer 5

So you find the slope of 3 here and apply it to the equation you found above