Question

The length of a rectangle is 3 times its width. The area is 56 sq cm. Find the dimensions of the rectangle.

Answer 1

l=3w
A=56
A=l x w, substitute l for w
A=3w x w, A=3w^2 solve for w
w=4.3
plug into l=3w
l=13
13 x 4.3 = 55.9

Answer 2

you flipped them, if length is three times width then length cannot be shorter than width

Answer 3

My mistake: Area=width*length
56=3x*x
56=3x^2
18.67=x^2
x=4.32
therefore: length=3*4.32
length=12.96cm
and width= 4.32cm