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Mathematics 7 Online
OpenStudy (anonymous):

Help! Will give a medal!

OpenStudy (anonymous):

what do you need help with?

OpenStudy (anonymous):

Let me attach the file 1 min

OpenStudy (anonymous):

OpenStudy (anonymous):

oh really sorry idk the answer only in 8th grade

OpenStudy (anonymous):

nvm

OpenStudy (anonymous):

@hartnn

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

Does anyone know functions? @ganeshie8

ganeshie8 (ganeshie8):

sorry i couldnt open the file... im on some junk unix machine :|

OpenStudy (anonymous):

Me too.

OpenStudy (anonymous):

Well let me type the question then

ganeshie8 (ganeshie8):

okie or a pic wud help too :)

OpenStudy (anonymous):

I saved it in a word file and attached it does it work here in openstudy

ganeshie8 (ganeshie8):

it works for most other users, for now im on a different machine. if u can, take a snapshot, save it as png/jpg file and attach the file

OpenStudy (anonymous):

It is a png img see if it works

OpenStudy (anonymous):

I saved that in paint

OpenStudy (anonymous):

wait

HanAkoSolo (jamierox4ev3r):

here I opened the file, and this is what is says: f:x-->2x-1 and g:x-->\(x^2\)-1 Find, in their simplest forms, a.) \(f^{-1}\)(x) b.)gf(x)

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

this is the pic

OpenStudy (anonymous):

yes that is the pic

ganeshie8 (ganeshie8):

ty :) you need to find inverse function of f

OpenStudy (anonymous):

Yes i got (x-1)/2

OpenStudy (anonymous):

is that right?

ganeshie8 (ganeshie8):

f:x-->2x-1 its same as :- f(x) = 2x-1 or y = 2x-1 solve for x

OpenStudy (anonymous):

Got the point of inverse functions

OpenStudy (anonymous):

(X-1)/2

ganeshie8 (ganeshie8):

y = 2x-1 y+1 = 2x (y+1)/2 = x switch x and y y = 2x-1 (x+1)/2 = y so the inverse function of f is, \(f^{-1} (x) = (x+1)/2\)

OpenStudy (anonymous):

And can u help me with the next question gf(X) composite function

ganeshie8 (ganeshie8):

g*f(x) = g(x) * f(x)

ganeshie8 (ganeshie8):

simply multiply both the functions and simplify them

OpenStudy (anonymous):

ohk let me do it 1 min

ganeshie8 (ganeshie8):

wait a sec, is it g(f(x)) ? or g * f(x) ?

OpenStudy (anonymous):

gf(x) is given in the question probably i think it is g(f(x)) because the answer is 4x^2-4x But i don't knw how they got it

ganeshie8 (ganeshie8):

then its definitely g(f(x)), g(f(x)) = g(_____)

ganeshie8 (ganeshie8):

fill the _____ wid the value of f(x)

OpenStudy (anonymous):

g(2x-1)

ganeshie8 (ganeshie8):

Yes !

ganeshie8 (ganeshie8):

g(x) = x^2 - 1 g(2x-1) = ?

OpenStudy (anonymous):

will it be 2(x^2-1)-1 ?

ganeshie8 (ganeshie8):

g(x) = x^2 - 1 g(2x-1) = (2x-1)^2 - 1

OpenStudy (anonymous):

but that does not simplify to the answer so it must not be

ganeshie8 (ganeshie8):

we just replace \( x\) wid \(2x-1\)

OpenStudy (anonymous):

Ohk u r of a great help thank u and wish u a happy diwali :)!!

OpenStudy (anonymous):

I got the point

ganeshie8 (ganeshie8):

you will need to use the (a-b)^2 formula.... (a-b)^2 = a^2 - 2ab + b^2

ganeshie8 (ganeshie8):

ohh np :) happy divali to you too !

OpenStudy (anonymous):

I got the exapansion

OpenStudy (anonymous):

thank u

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