Mathematics
7 Online
OpenStudy (anonymous):
Help! Will give a medal!
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OpenStudy (anonymous):
what do you need help with?
OpenStudy (anonymous):
Let me attach the file 1 min
OpenStudy (anonymous):
OpenStudy (anonymous):
oh really sorry idk the answer only in 8th grade
OpenStudy (anonymous):
nvm
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OpenStudy (anonymous):
@hartnn
OpenStudy (anonymous):
@ganeshie8
OpenStudy (anonymous):
Does anyone know functions? @ganeshie8
ganeshie8 (ganeshie8):
sorry i couldnt open the file... im on some junk unix machine :|
OpenStudy (anonymous):
Me too.
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OpenStudy (anonymous):
Well let me type the question then
ganeshie8 (ganeshie8):
okie or a pic wud help too :)
OpenStudy (anonymous):
I saved it in a word file and attached it does it work here in openstudy
ganeshie8 (ganeshie8):
it works for most other users,
for now im on a different machine. if u can, take a snapshot,
save it as png/jpg file and attach the file
OpenStudy (anonymous):
It is a png img see if it works
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OpenStudy (anonymous):
I saved that in paint
OpenStudy (anonymous):
wait
HanAkoSolo (jamierox4ev3r):
here I opened the file, and this is what is says:
f:x-->2x-1 and g:x-->\(x^2\)-1
Find, in their simplest forms,
a.) \(f^{-1}\)(x) b.)gf(x)
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
this is the pic
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OpenStudy (anonymous):
yes that is the pic
ganeshie8 (ganeshie8):
ty :)
you need to find inverse function of f
OpenStudy (anonymous):
Yes i got (x-1)/2
OpenStudy (anonymous):
is that right?
ganeshie8 (ganeshie8):
f:x-->2x-1
its same as :-
f(x) = 2x-1
or
y = 2x-1
solve for x
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OpenStudy (anonymous):
Got the point of inverse functions
OpenStudy (anonymous):
(X-1)/2
ganeshie8 (ganeshie8):
y = 2x-1
y+1 = 2x
(y+1)/2 = x
switch x and y
y = 2x-1
(x+1)/2 = y
so the inverse function of f is,
\(f^{-1} (x) = (x+1)/2\)
OpenStudy (anonymous):
And can u help me with the next question gf(X) composite function
ganeshie8 (ganeshie8):
g*f(x) = g(x) * f(x)
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ganeshie8 (ganeshie8):
simply multiply both the functions
and simplify them
OpenStudy (anonymous):
ohk let me do it 1 min
ganeshie8 (ganeshie8):
wait a sec,
is it g(f(x)) ?
or g * f(x) ?
OpenStudy (anonymous):
gf(x) is given in the question probably i think it is g(f(x)) because the answer is 4x^2-4x
But i don't knw how they got it
ganeshie8 (ganeshie8):
then its definitely g(f(x)),
g(f(x)) = g(_____)
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ganeshie8 (ganeshie8):
fill the _____ wid the value of f(x)
OpenStudy (anonymous):
g(2x-1)
ganeshie8 (ganeshie8):
Yes !
ganeshie8 (ganeshie8):
g(x) = x^2 - 1
g(2x-1) = ?
OpenStudy (anonymous):
will it be 2(x^2-1)-1 ?
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ganeshie8 (ganeshie8):
g(x) = x^2 - 1
g(2x-1) = (2x-1)^2 - 1
OpenStudy (anonymous):
but that does not simplify to the answer so it must not be
ganeshie8 (ganeshie8):
we just replace \( x\) wid \(2x-1\)
OpenStudy (anonymous):
Ohk u r of a great help thank u and wish u a happy diwali :)!!
OpenStudy (anonymous):
I got the point
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ganeshie8 (ganeshie8):
you will need to use the (a-b)^2 formula....
(a-b)^2 = a^2 - 2ab + b^2
ganeshie8 (ganeshie8):
ohh np :)
happy divali to you too !
OpenStudy (anonymous):
I got the exapansion
OpenStudy (anonymous):
thank u