Question

Write an equation of a line in slope intercept form that is parallel to y=3x+6 and passes through the point (-10, 2.5)

Answer 1

Let us first find the slope of y=3x+6
comparing y=3x+6 with
y=mx+c we find
slope m= 3 and y-intercept c = 6
Since parallel lines have same slope.
therefore slope (m) of the required line is also = 3
since line passes through the point (-10, 2.5)
Equation of line in slope -point form is given as;
\[\huge y-y_1 =m(x-x_1)\]
where \[\huge x_1 =-10\] & \[\huge y_1 =2.5\] Now substituting the values of m, x1 & y1 in the above equation we find;

\[\huge y-2.5 =3[x-(-10)]\]
\[\huge y-2.5 =3[x+10] \rightarrow \huge y-2.5 =3x+30\]
\[\rightarrow \huge y =3x+30+2.5 \rightarrow \huge y =3x+32.5\]
Hence y =3x+32.5 is the required equation of the line.

@sky6298

Answer 2

@sky6298

Answer 3

Thank you!