Question

determine the equation whose roots are -3, -3 and 3

Answer 1

Any root \(a\) of a polynomial equation comes form a factor \(x - a\).

Answer 2

a. x^3+3x^2-9x-27=0
b. x^3-9x^2+27x+8=0
c. x^3-3x^2+9x=0
d. x^3-3x^2+8x=0

Answer 3

Well which one can you eliminate right away?

Answer 4

\( [x - (-3)][x - (-3)][x - 3] \)

\( = (x + 3)(x + 3)(x - 3) \)

Look at the last terms: 3, 3, -3.
When you multiply then together, what do you get?

Answer 5

Hint: you can get rid of the answers with even numbers in them. :D

Answer 6

so its c

Answer 7

Work it out.

Answer 8

Did you find the product of 3, 3, and -3?

Answer 9

(x-3)(x+3)^2 what gives you this expression?

Answer 10

ahhh @iambatman your not helping!! lol jk how do you set it up first