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Mathematics 6 Online
OpenStudy (anonymous):

solve x(x + 5) = 0

OpenStudy (anonymous):

If something multiplied by something is zero, then one of those things must be 0. In the context of solving an equation like this, you can set both parts equal to 0 and solve.

jimthompson5910 (jim_thompson5910):

hint: if A*B = 0 then A = 0 or B = 0

OpenStudy (anonymous):

yes. x squared + 5x = 0

OpenStudy (anonymous):

You don't want to distribute, Luke. That just sets you back a step.

OpenStudy (lukecrayonz):

Not at all..

OpenStudy (anonymous):

i have to solve for x right?

OpenStudy (anonymous):

Young Jeezy, if A*B = 0, then either A or B must be 0, yes? So x(x+5) is the same as A*B.

OpenStudy (anonymous):

Yes, you are trying to solve for x.

OpenStudy (anonymous):

which is A and which is B?

OpenStudy (anonymous):

It doesn't matter. A*B = 0 is just a rule. You can make x be the A and (x+5) be the B or visa versa. The rule is just to help you understand that from here, to solve for x, you have to set both parts equal to zero, then solve.

OpenStudy (anonymous):

I'll give you a hint that may help clear up some confusion: there are TWO answers to for x in this problem. Not just one.

OpenStudy (anonymous):

then the answer is + - a square root of a number

OpenStudy (anonymous):

Not necessarily. There are other ways you can have two answers.

OpenStudy (anonymous):

Take both parts of the equation you have left, the X and the X+5, and set each one to zero. o x = 0 and x+5 = 0. Then try solving.

OpenStudy (anonymous):

is the answer square root of 5 and negative square root of 5?

OpenStudy (anonymous):

No, it's not. You are one step away from solving it. Don't try to mess with the x(x+5). That's what you need. Now take each factor (the x and the x+5) and separately set them equal to 0. Then solve.

OpenStudy (anonymous):

if x=0 then i can substitute x in the x+5=0 equation, or no?

OpenStudy (anonymous):

No, once you split them apart to solve, they become "separate" equations. Solve each one on its own.

OpenStudy (anonymous):

well, x=0, isnt that already solved?

OpenStudy (anonymous):

Yep

OpenStudy (anonymous):

But this problem has more than one answer, as I said before.

OpenStudy (anonymous):

so if x+5=0,i have to leave x by itself. so it would become x= -5

OpenStudy (anonymous):

Yes sir. So x = 0, -5

OpenStudy (anonymous):

i got it! thank you so much. i really needed to know this.

OpenStudy (anonymous):

Just remember, if you ever have "something" multiplied by "something else" and it's equal to zero, you can solve that by setting each different factor equal to zero and solving.

OpenStudy (anonymous):

And there CAN BE more than one answer!

OpenStudy (anonymous):

i get it now :) thanks for the help

OpenStudy (anonymous):

No problem.

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