For positive constants k and g, the velocity, v, of a particle of mass m at time t is given by:
v=(mg/k)(1-e^(-kt/m))
At what rate is the velocity changing at t=0? at t=8?

Question

For positive constants k and g, the velocity, v, of a particle of mass  m at time t is given by:
v=(mg/k)(1-e^(-kt/m))
At what rate is the velocity changing at t=0? at t=8?

anonymous · Answer

The rate of change of the velocity is the derivative of the velocity function. Take the derivative of the function, then plug in t = 0 and t = 8 to find the rate of change at those points.

anonymous · Answer

Are you given k, g, and m?

anonymous · Answer

If you're not given k, g, and m, you shouldn't be able to get a number when you plug in t. The best you'll be able to do is get the acceleration at time t with respect to k, g, and m. What was your derivative?