Question

f(x)=e^(-((x-3)^2)/32).....this is the only one I cannot figure out. My teacher is sadistic

Answer 1

\[f(x)=e^(-((x-3)^2)/32)\]

Answer 2

What's the question?

Answer 3

oh, sorry. what is f '(x)?

Answer 4

Remember that the derivative of e^x is just e^x dx. To solve the rest of the exponent, you need to use the chain rule.

Answer 5

isn't it \[e^u(u'); u=-((x-3)^2)/32\]

Answer 6

\[e^(-(x-3)^2)/32 \] multiplied by \[(x-3)/16\]?

Answer 7

Yes, that's it.

Answer 8

That's what I thought, I don't know why it's not working for me. I guess I'll have to ask him tomorrow. Just wanted to make sure I was doing it right. Thanks for the help