Help? /: Particular equation of the transformed sine graph? pic attached. Thanks for any help!
Why are some words blocked?o-O
Those arent really important >.<
@Yuba
Since, you asked too many questions from this, See, when a function y=f(x) is shifted vertically, it changes to y+k = f(x) .. [ k is positive when shifted downward by k units and negative when shifted upwards by k units] when a graph of y= f(x) is shifted horizontally, it changes to y= f(x+k) [ k>0 for leftward shift by k units and k<0 for rightward shift] And as far as finding the center of the sinusoidal curve is concerned, See that this is a sinusoidal curve, y= Sin x which is shifted, two units up and half units right.. Now use above info to find your resulting equation..
its one question? ._.
looks like the graph of \(y=-\cos(x)\) but with certain adjustments one is that instead of going from -1 to 1 it goes from -2 to 6, which has length 8 that means the amplitude is 4, so it is some sort of \(y=-4\cos(x)\) now you have to adjust for the period
period looks to be 4 the period of \(-4\cos(bx)\) is \(\frac{2\pi}{b}\) so set \(\frac{2\pi}{b}=4\) and solve for \(b\)
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