giving out a medal if you know how to explain this to me . how do you solve this equation? (3x+4x+1)+(2x^2+5x-8)
which school do you go to
connexus
scca
The problem to solve is: (3x+4x+1)+(2x^2+5x-8) Multiply x and 3 Multiply x and 1 The x just gets copied along. The answer is x x 3*x evaluates to 3x Multiply x and 4 Multiply x and 1 The x just gets copied along. The answer is x x 4*x evaluates to 4x 3*x+4*x evaluates to 7x 3*x+4*x+1 evaluates to 7x+1 Multiply the exponent of x by 2giving The answer is x^2 evaluates to Multiply and 2 Multiply and 1 The just gets copied along. The answer is 2*x^2 evaluates to Multiply x and 5 Multiply x and 1 The x just gets copied along. The answer is x x 5*x evaluates to 5x 2*x^2+5*x evaluates to The answer is 2*x^2+5*x-8 evaluates to To add the polynomials 7x+1 and we try to add or combine terms in one polynomialwith any like terms in the other polynomial. 7x + 5x = 12x 1 + -8 = -7 The answer is (3*x+4*x+1)+(2*x^2+5*x-8) evaluates to 12x-7+2x^2
copy: " how do you solve this equation?" question: if it is an equation, where is = sign?
@Loser66 he means to say simplify
ok hold on
@mathman806 maybe, sometimes I turn to madman to frustrate with nothing, hehehe
hehehe
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