With a tail wind, a helicopter traveled 300mi in an hour and 40 min. the return trip against the same wind took 20 min longer. find the wind speed and also the air speed of the helicopter.
You can use a equation to solve this question. Consider the speed of wind as x.
okay
The equation is 1/3*(300+x)=1*(300-x), do you know why?
no i got a system of equations.... I said p=air speed and w= wind speed 5/3(p+w)=300 2(p-w)=300
My equation is easy to solve. Distance=time*speed, all right?
i dont understand it
Is the speed of helicopter 300miles per hour?
yes
The speed of the helicopter traveled with trial wind was 300+x, for wind was pushing it forward; the speed of the helicopter came back was 300-x, for wind was pushing it backward, isn't?
yes
The distance the helicopter traveled can be represented by 1/3*(300+x) and 1*(300-x). So we get 1/3*(300+x)=1*(300-x).
why 1/3?
isnt it 5/3 though because it 1hr and 4o min
Oh, I know. So the equation should be 5/3*(300+x)=2*(300-x), right this time?
Thank for your reminding!
okay hold on
27.3?
thats not the answer though
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