Who do you do you think correct and why Jameel and Sarah are discussing how to factor 3b2 + 8b + 4. Jameel feels this trinomial is prime because he cannot find factors of 4 that have a sum of 8. Sarah says he is incorrect and that it is factorable.
@Chineseboy15 @UditKulka @Hello_Im_Nick @austinL
@heyitsminnaaax3
Sarah is right.
3b2+8b+4 is factorable for 3b2+8b+4=2(3b+4b+2). So Sarah is right.
thank you both
Sarah is right. It is true that no factors of four multiply to 8, but Jamaal is forgetting the 3b^2. Since the factors of 3b^2 are 3b and b, you could set up an expression like this: (3b+x)(b+y) 3y and x will add to 8, and x(y) will multiply to 4 (3b+2)(b+2) simplify this (3b^2+6b+2b+4 simplify further 3b^2+8b+4 and there is your starting answer. therefore the factors are (3b+2)(b+2) to create a prime trinomial set a as 1 and then find a b and c that don't factor like b=5, c=2
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