2x=sqrt10+3x
tell me the first step and i'll work the whole problem by myself. The answer is x=2 but i keep getting x=10 here's what i did i hired the powers first (2x)^2=(sqrt10+3x)^2 but if i do this method first, the answer is x=10
are you sure its x = 2?
you are sure its not x = -sqrt10
yeah, that's what it says at the back of the text-book
let me double check, hold on
yup it's 2 :/
maybe you combince like terms i have no idea srry...
ok, thanks for trying :)
@amistre64 @shrutipande9 @helppls123 didn't want to bother you but can you help this person?
@campbell_st
is the question 1. \[2x = \sqrt{10} + 3x\] or 2. \[2x = \sqrt{10 + 3x}\]
the second one :)
ok square both sides \[4x^2 = 10 + 3x\] rewrite the equation and its \[4x^2 -3x -10 = 0\] just solve the quadratic, and it can be factored.
that's what i got, so all have to do do is plug in the quadratic formula and that's it?
wait, how come 2x became 4x^2 should it be 4x and since it's already squared?
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