draw the graph of: y=sin0{0≤0≤720}
Dammit... Let me make it abit more... clear: If you mean something like \[ y=sin(\theta ^\circ) \quad \quad \{ 0^\circ≤ \theta ≤720^\circ \} \] Then since 720 / 180 = 4 we can say: \[ y=sin(x) \quad \quad \{ 0≤x≤4 \pi \} \] To get this in radians.. and now it looks like this: http://www.wolframalpha.com/input/?i=sin%28x%29%2C+0%3Cx%3C4pi The function of sinus, but with domain of \(0\) to \(4π\)
what is the ampliturde and period?
Well, you just limited the domain.. this has same period and amplitude of sin(x). So the pick amplitude is 1 to -1. pick to pick amplitude is 2.. and the period is \(2 \pi \)
so is it 2pi sin 2?
function: \( y = sin(x) \) amplitude: 1 to -1 pick to pick amplitude: |1| + |-1| = 2 period \(2 \pi \) Not sure what you meant.
If they are asking for a single value of peak amplitude they probably wanna hear 1 (not -1). peak to peak amplitude is still 2 though.
what i mean is:|dw:1383688404088:dw|
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