An algebra test contains 38 problems. some of the problems are worht 2 points each and the rest are worth 3 poins each. A perfect score is 100 points. How many problems are worth 2 points?
you need 2 equations: 38 problems, 2 types (1) 38=x+y these have to sum up to 100, so (2) 3x + 2y = 100 Now substitute one into the other (I suggest (1) into (2)) and solve.
so whats the answer? i wana make sure i got the right one
post what you did if you want me to check whether it's right or not
3x+2(1)=100 3x+2=100 -2 -2 3x=98 98 divided 3 is 32.6
why did you plug in 1 into y?
didnt u say that?
i meant equation (1), not the number one...
ohhh okay let me trye again
okay
idk what to do! ikno im suppose to plug it in but how? is this correct: 3x+2(38)=100
nope, you need to isolate a variable, say x: 38=x+y -> x=38-y then plug that into the second equation
ohhh so 3(38-y)+2y=100
yeah thats it, then solve for y. once you know y, you can find x (by using the first equation).
remember what those variables represent though
okay thank you soo much do u think u can help me with something else?
and for the answer i got 14
thats right
sure, shoot
okay so write the function h(x)=-5(x-1)^2+3
in standard form
expand this bracket (x-1)^2, then distribute 5 to all the terms within it then simplify
you should be asking these questions in the math section :P
im new to this so idknow how to work this website out
no worries. it's up at the top, click on "Find More Subjects" and a menu will pop up.
its not letting me it freezes :(
could u help me with this??
I can't help you with all of that at the moment, but i can give you a link to get to the math section http://openstudy.com/study#/groups/Mathematics
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