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Determine whether or not the graph of f has a vertical tangent or a vertical cusp at c. I don't fully understand how to do it. (x+3)^4/3; c=-3 I know that you differentiate it f'(x)=4/3(x+3)^1/3 but I don't know what to do from here.
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Alright, so recall that the derivative is simply the rate of change of a function. When the function it is not changing, it is at a concave point wherein \(f'(x) = 0\). When the function is undefined, it has a vertical slope. When is the function \(\frac 4 3 (x+3)^{1/3}\) undefined?
-3
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Honestly, I don't know what to do. Are you saying make the derivative equal to 0?
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