Mathematics
7 Online
OpenStudy (ammarah):
Factor the polynomial completely using any method. Sum or difference of cubes or by grouping.
x^3-512
-3y^3-24
y^4-81
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OpenStudy (ammarah):
@nikato
OpenStudy (nikato):
i'll try. kinda forgot about this from last year.. but do you know like the special frmulas for factoring cubes
OpenStudy (anonymous):
\[(x-8)(x ^{2} + 8x + 64)\]
OpenStudy (nikato):
a3 + b3 = (a + b)(a2 – ab + b2)
a3 – b3 = (a – b)(a2 + ab + b2)
do you know this? special formulas for cubes
OpenStudy (anonymous):
On the second one if you factor out -3 it will help a lot.
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OpenStudy (ammarah):
so the second one is -3(y^3+8)
OpenStudy (anonymous):
Yeah. Where a = y and b = 2
OpenStudy (ammarah):
so what would that be?
OpenStudy (anonymous):
(y + 2)(y^2 + 2y + 4)
OpenStudy (ammarah):
how about the thir d one
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OpenStudy (ammarah):
wait ill tell u what i got
OpenStudy (anonymous):
Not sure about that one
OpenStudy (nikato):
third one... its a special kind of factoring using this fromula
(x-y)(x+y)=x^2-y^2
OpenStudy (ammarah):
idk how t solve it...
OpenStudy (anonymous):
\[(y ^{2} + 9)(y ^{2} -9)\] and solve for that
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OpenStudy (ammarah):
how do i solve?
OpenStudy (anonymous):
So try to factor each one individually.
OpenStudy (anonymous):
First one doesn't factor.
OpenStudy (ammarah):
y+3 and y-3
OpenStudy (anonymous):
\[(y ^{2} + 9)(y + 3)(y -3)\]
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OpenStudy (ammarah):
yes
OpenStudy (anonymous):
Good job
OpenStudy (ammarah):
i need more help on a diff question
OpenStudy (anonymous):
sure what is it