Question

Solve and check each of the equations:

x^2-4x+3=0



x^2+6x+5=0



4-x(x-3)=0



3x^2-5x=36-2x



2x(x+1) =12

Answer 1

\[x1 and x2=\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\] when \[ax ^{2}+bx+c=0\]

Answer 2

but you can often use a quick simpler method. find the factors of c that add to give b
so for example the first equation \[x^2 -4x +3 = 0\] factors of +3 are -1 and -3 they add to give -4 so we know to use those two factors like such \[(x-1) (x-3) \] and thats the first question factored the easy way.

Answer 3

so for the equation to equal zero x = 1 or x = 3, check it by using the 1 and 3 in the original equation and if it's zero , then all good :)

Answer 4

try the second one now and see how you go ?