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Find two numbers whose product is -40, and whose sum is 3
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well; (2+n) + (1-n) = 3 (2+n)(1-n) = -40 ... solve for n to determine the numbers ....
6?
6 feels good ... 8-5 = 3, and 8(-5) = -40
And -7 for the first part?
(2+n) + (1-n) = 3 6 6 8 + (-5) = 3, is good (2+n)(1-n) = -40 6 6 8 (-5) = -40 this is a method that some guy in greece used ... i think his name was diophantus
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