Question

what are the real or imaginary solutions of the polynomial equation x^4 -52x^2+576=0

Answer 1

\[x^4 -52x^2+576=0 --> x^2(x^2 -52)+576=0-->x^2(x^2 -52)=-576\]so two of the answers will be, \[x=±\sqrt{24}\]. now work the \[(x^2 -52)=-576-->x^2 -52+576=0-->x^2+524=0-->x=±i \sqrt{524}\]\[x=±i \sqrt{524}--->x=±2i \sqrt{131}\]
So, \[x=±\sqrt{24}\]OR\[x=2i±\sqrt{131}\]

Answer 2

thats not an option?

Answer 3

What are they?

Answer 4

A. 4, -4
B. 4, -6
C. 4, -4,6,-6
D. no solution

Answer 5

Oh....

Answer 6

lol

Answer 7

\[ x^4 -52x^2=-576\]plug in your coordinates I guess....

Answer 8

you can factor the left side out of x^2 if you think it will be easier this way.

Answer 9

@hartnn @hba @allie_bear22

Answer 10

Yeah, I figured how to do it, when I saw this question again.

say let x^2=a

substitute a for x^2 and solve for a, then substitute the result for a into x^2=a

@Jelia97

Answer 11

ok

Answer 12

What do you get? Tell me when you find x.

Answer 13

it was 4, -4,6, -6

Answer 14

Did you submit? I meant what you get as a solution to x.