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A solution contains 9.2x10 -3 M in CU 2+ and 0.73 M in LiCN. If the Kf for Cu(CN)4 2- is 1.0x10 25, how much copper ion remains at equilibrium?
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\[9.2x10^-3 M Cu^2+\]\[0.73 M LiCN\] Kf\[Cu(CN)_{4}^{2-}\] is \[1.0x10^{25}\], How much copper ion remains at equilibrium?
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